The unit digit of a number raised to a power can be found by looking at the cyclicity of the unit digit.

1. For 6324^1797, the unit digit is 4. The cyclicity of 4 is {4, 6}, which repeats every 2 powers. So, the unit digit of 6324^1797 is 4 because 1797 is odd.

2. For 615^316, the unit digit is 5. The unit digit of any power of 5 is always 5.

3. For 341^476, the unit digit is 1. The unit digit of any power of 1 is always 1.

Now, multiply the unit digits together: 4 * 5 * 1 = 20. The unit digit of 20 is 0.

So, the unit digit of (6324)^1797 * (615)^316 * (341)^476 is 0.

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The unit digit of a number raised to a power can be found by looking at the cyclicity of the unit digit.

1. For 6324^1797, the unit digit is 4. The cyclicity of 4 is {4, 6}, which repeats every 2 powers. So, the unit digit of 6324^1797 is 4 because 1797 is odd.

2. For 615^316, the unit digit is 5. The unit digit of any power of 5 is always 5.

3. For 341^476, the unit digit is 1. The unit digit of any power of 1 is always 1.

Now, multiply the unit digits together: 4 * 5 * 1 = 20. The unit digit of 20 is 0.

So, the unit digit of (6324)^1797 * (615)^316 * (341)^476 is 0.

Knowee AI · Accepted Answer

The unit digit of a number raised to a power can be found by looking at the cyclicity of the unit digit.

1. For 6324^1797, the unit digit is 4. The cyclicity of 4 is {4, 6}, which repeats every 2 powers. So, the unit digit of 6324^1797 is 4 because 1797 is odd.

2. For 615^316, the unit digit is 5. The unit digit of any power of 5 is always 5.

3. For 341^476, the unit digit is 1. The unit digit of any power of 1 is always 1.

Now, multiply the unit digits together: 4 * 5 * 1 = 20. The unit digit of 20 is 0.

So, the unit digit of (6324)^1797 * (615)^316 * (341)^476 is 0.

What is the unit digit in (6324)1797×(615)316×(341)476 ?Options :054non

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