Sure, let's find the axis of symmetry for the quadratic function $ y = x^2 - 4x + 13 $.

The general form of a quadratic function is $ y = ax^2 + bx + c $. For this function, we have:
- $ a = 1 $
- $ b = -4 $
- $ c = 13 $

The formula to find the axis of symmetry for a quadratic function is given by:
$$ x = -\frac{b}{2a} $$

Now, let's substitute the values of $ a $ and $ b $ into the formula:

1. Identify $ a $ and $ b $:
$$ a = 1 $$
$$ b = -4 $$

2. Substitute $ a $ and $ b $ into the formula:
$$ x = -\frac{-4}{2 \cdot 1} $$

3. Simplify the expression:
$$ x = -\frac{-4}{2} $$
$$ x = \frac{4}{2} $$
$$ x = 2 $$

So, the axis of symmetry for the quadratic function $ y = x^2 - 4x + 13 $ is $ x = 2 $.

Question

Sure, let's find the axis of symmetry for the quadratic function $ y = x^2 - 4x + 13 $.

The general form of a quadratic function is $ y = ax^2 + bx + c $. For this function, we have:
- $ a = 1 $
- $ b = -4 $
- $ c = 13 $

The formula to find the axis of symmetry for a quadratic function is given by:
$$ x = -\frac{b}{2a} $$

Now, let's substitute the values of $ a $ and $ b $ into the formula:

1. Identify $ a $ and $ b $:
   $$ a = 1 $$
   $$ b = -4 $$

2. Substitute $ a $ and $ b $ into the formula:
   $$ x = -\frac{-4}{2 \cdot 1} $$

3. Simplify the expression:
   $$ x = -\frac{-4}{2} $$
   $$ x = \frac{4}{2} $$
   $$ x = 2 $$

So, the axis of symmetry for the quadratic function $ y = x^2 - 4x + 13 $ is $ x = 2 $.

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