Instructions: For the following quadratic functions, write the function in factored form and then find the x𝑥-intercepts, axis of symmetry, vertex, and domain and range.y=x2−2x−15𝑦=𝑥2−2𝑥−15Factored Form: y=(x𝑦=(𝑥 Answer 1 Question 18 Answer 2 Question 18 )(x)(𝑥 Answer 3 Question 18 Answer 4 Question 18 )) (Type least to greatest.)x𝑥-Intercepts: (( Answer 5 Question 18 ,, Answer 6 Question 18 )) and (( Answer 7 Question 18 ,, Answer 8 Question 18 )) (Type least to greatest.)Axis of Symmetry: x=𝑥= Answer 9 Question 18Vertex: (( Answer 10 Question 18 ,, Answer 11 Question 18 ))Domain: Answer 12 Question 18Range: y𝑦 Answer 13 Question 18 Answer 14 Question 18

The given quadratic function is y = x^2 - 2x - 15.

1. Factored Form: To write the function in factored form, we need to factorize the quadratic equation. The factors of -15 that add up to -2 are -5 and 3. So, the factored form of the equation is y = (x - 5)(x + 3).

2. x-intercepts: The x-intercepts are the values of x for which y = 0. Setting the factored form of the equation to zero gives us x - 5 = 0 and x + 3 = 0. Solving these equations gives us x = 5 and x = -3. So, the x-intercepts are (5, 0) and (-3, 0).

3. Axis of Symmetry: The axis of symmetry for a quadratic function y = ax^2 + bx + c is given by the formula x = -b/2a. Here, a = 1 and b = -2. So, the axis of symmetry is x = -(-2)/2*1 = 1.

4. Vertex: The vertex of the function is the point (h, k) where h is the axis of symmetry and k is the value of the function at h. So, h = 1 and k = (1)^2 - 2*(1) - 15 = -16. So, the vertex is (1, -16).

5. Domain: The domain of a quadratic function is all real numbers, since the function is defined for all x.

6. Range: The range of a quadratic function y = ax^2 + bx + c, where a > 0, is [k, ∞) and where a < 0, is (-∞, k]. Here, a = 1 which is greater than 0 and k = -16. So, the range is [-16, ∞).