Instructions: Given the quadratic function, find the x𝑥-value of the vertex (axis of symmetry).y=x2+4x−10
Question
Instructions: Given the quadratic function, find the x𝑥-value of the vertex (axis of symmetry).y=x2+4x−10
Solution
The x-value of the vertex (axis of symmetry) of a quadratic function given in the form y = ax^2 + bx + c is given by the formula -b/2a.
In the given function y = x^2 + 4x - 10, the coefficients are a = 1 and b = 4.
Substituting these values into the formula, we get:
x = -b/2a = -4/(2*1) = -4/2 = -2
So, the x-value of the vertex of the given quadratic function is -2.
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