The vertex of the function y = 2(x - 4)² - 1 is given by the point (h, k), where h is the value inside the brackets and k is the constant at the end.

In this case, h = 4 and k = -1.

So, the vertex of the function is at the point (4, -1).

Question

The vertex of the function y = 2(x - 4)² - 1 is given by the point (h, k), where h is the value inside the brackets and k is the constant at the end.

In this case, h = 4 and k = -1.

So, the vertex of the function is at the point (4, -1).

Knowee AI · Accepted Answer

The vertex of the function y = 2(x - 4)² - 1 is given by the point (h, k), where h is the value inside the brackets and k is the constant at the end.

In this case, h = 4 and k = -1.

So, the vertex of the function is at the point (4, -1).

Instructions: Given the function, state the vertex.y=2(x−4)2−1