The vertex of a parabola given by the equation y = ax^2 + bx + c is given by the point (h, k), where h = -b/2a and k = c - b^2/4a.

In the equation y = -2x^2 - 4x - 5, a = -2, b = -4, and c = -5.

Step 1: Calculate h
h = -b/2a = -(-4)/2*(-2) = 4/-4 = -1

Step 2: Calculate k
k = c - b^2/4a = -5 - (-4)^2/4*(-2) = -5 - 16/-4 = -5 + 4 = -1

So, the vertex of the parabola y = -2x^2 - 4x - 5 is (-1, -1).

Question

The vertex of a parabola given by the equation y = ax^2 + bx + c is given by the point (h, k), where h = -b/2a and k = c - b^2/4a.

In the equation y = -2x^2 - 4x - 5, a = -2, b = -4, and c = -5.

Step 1: Calculate h
h = -b/2a = -(-4)/2*(-2) = 4/-4 = -1

Step 2: Calculate k
k = c - b^2/4a = -5 - (-4)^2/4*(-2) = -5 - 16/-4 = -5 + 4 = -1

So, the vertex of the parabola y = -2x^2 - 4x - 5 is (-1, -1).

Knowee AI · Accepted Answer

The vertex of a parabola given by the equation y = ax^2 + bx + c is given by the point (h, k), where h = -b/2a and k = c - b^2/4a.

In the equation y = -2x^2 - 4x - 5, a = -2, b = -4, and c = -5.

Step 1: Calculate h
h = -b/2a = -(-4)/2*(-2) = 4/-4 = -1

Step 2: Calculate k
k = c - b^2/4a = -5 - (-4)^2/4*(-2) = -5 - 16/-4 = -5 + 4 = -1

So, the vertex of the parabola y = -2x^2 - 4x - 5 is (-1, -1).

What is the vertex of y = −2x2 – 4x – 5?