Instructions: For the following quadratic functions, write the function in factored form and then find the x𝑥-intercepts, axis of symmetry, vertex, and domain and range.y=x2+4x+3𝑦=𝑥2+4𝑥+3Factored Form: y=(x𝑦=(𝑥 Answer 1 Question 4 Answer 2 Question 4 )(x)(𝑥 Answer 3 Question 4 Answer 4 Question 4 )) (Type least to greatest.)x𝑥-Intercepts: (( Answer 5 Question 4 ,, Answer 6 Question 4 )) and (( Answer 7 Question 4 ,, Answer 8 Question 4 )) (Type least to greatest.)Axis of Symmetry: x=𝑥= Answer 9 Question 4Vertex: (( Answer 10 Question 4 ,, Answer 11 Question 4 ))Domain: Answer 12 Question 4Range: y𝑦 Answer 13 Question 4 Answer 14 Question 4

The given quadratic function is y = x^2 + 4x + 3.

1. Factored Form: To write the function in factored form, we need to factorize the quadratic equation. The factored form of the equation is y = (x + 1)(x + 3).

2. x-intercepts: The x-intercepts are the values of x for which y = 0. Setting the factored form of the equation to zero gives us x + 1 = 0 and x + 3 = 0. Solving these equations gives us x = -1 and x = -3. So, the x-intercepts are (-1, 0) and (-3, 0).

3. Axis of Symmetry: The axis of symmetry for a quadratic function y = ax^2 + bx + c is given by x = -b/2a. Here, a = 1 and b = 4. So, the axis of symmetry is x = -4/(2*1) = -2.

4. Vertex: The vertex of the function is the point on the graph where the axis of symmetry intersects the function. It is given by the point (-b/2a, f(-b/2a)). Here, f(-b/2a) = (-2)^2 + 4*(-2) + 3 = -1. So, the vertex is (-2, -1).

5. Domain: The domain of a quadratic function is all real numbers, since x can take any real value.

6. Range: The range of a quadratic function y = ax^2 + bx + c, where a > 0, is [f(-b/2a), ∞). Here, f(-b/2a) = -1. So, the range is [-1, ∞).