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What will be the output of the following Python code?def foo(x): x[0] = ['def'] x[1] = ['abc'] return id(x)q = ['abc', 'def']print(id(q) == foo(q))

Question

What will be the output of the following Python code?def foo(x): x[0] = ['def'] x[1] = ['abc'] return id(x)q = ['abc', 'def']print(id(q) == foo(q))

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Solution

The output of the given Python code will be True.

Here's the step-by-step explanation:

  1. A list q is defined with two elements: 'abc' and 'def'.
  2. The id() function in Python returns the “identity” of an object, which is unique and constant for this object during its lifetime. So, id(q) returns the unique id of the list q.
  3. The function foo(x) is defined, which takes a list as an argument. Inside this function, the first and second elements of the list are modified to ['def'] and ['abc'] respectively. Then, the function returns the id of the modified list.
  4. foo(q) is called with q as the argument. Inside the function, q is modified and the id of the modified q is returned.
  5. id(q) == foo(q) compares the id of the original list q with the id returned by foo(q). Since the list q is modified in-place inside the function foo, its id remains the same. Therefore, the comparison returns True.
  6. print(id(q) == foo(q)) prints the result of the comparison, which is True.

This problem has been solved

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