What will be the output of the following Python code?def foo(x): x[0] = ['def'] x[1] = ['abc'] return id(x)q = ['abc', 'def']print(id(q) == foo(q))
Question
What will be the output of the following Python code?def foo(x): x[0] = ['def'] x[1] = ['abc'] return id(x)q = ['abc', 'def']print(id(q) == foo(q))
Solution
The output of the given Python code will be True.
Here's the step-by-step explanation:
- A list
qis defined with two elements: 'abc' and 'def'. - The
id()function in Python returns the “identity” of an object, which is unique and constant for this object during its lifetime. So,id(q)returns the unique id of the listq. - The function
foo(x)is defined, which takes a list as an argument. Inside this function, the first and second elements of the list are modified to ['def'] and ['abc'] respectively. Then, the function returns the id of the modified list. foo(q)is called withqas the argument. Inside the function,qis modified and the id of the modifiedqis returned.id(q) == foo(q)compares the id of the original listqwith the id returned byfoo(q). Since the listqis modified in-place inside the functionfoo, its id remains the same. Therefore, the comparison returnsTrue.print(id(q) == foo(q))prints the result of the comparison, which isTrue.
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