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What will be the output of the following Python code snippet?print([[i+j for i in "abc"] for j in "def"])

Question

What will be the output of the following Python code snippet?print([[i+j for i in "abc"] for j in "def"])

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Solution 1

The output of the given Python code snippet will be a list of lists. Here's how it works:

  1. The outer list comprehension for j in "def" iterates over each character in the string "def". For each character j, it creates a new list.

  2. The inner list comprehension for i in "abc" iterates over each character in the string "abc". For each character i, it adds i to j and this new string is an element in the new list.

  3. The result is a list of these new lists.

So, the output will be:

[['ad', 'bd', 'cd'], ['ae', 'be', 'ce'], ['af', 'bf', 'cf']]

Each inner list corresponds to a character in "def", and the strings in the inner lists are the characters in "abc" concatenated with that character.

This problem has been solved

Solution 2

The output of the given Python code snippet will be a list of lists. The outer list comprehension for j in "def" will iterate over each character in the string "def". For each character j, it will create a new list using the inner list comprehension for i in "abc".

The inner list comprehension will iterate over each character in the string "abc", and for each character i, it will calculate the expression i+j, which is the concatenation of the strings i and j.

So, the output will be:

[['ad', 'bd', 'cd'], ['ae', 'be', 'ce'], ['af', 'bf', 'cf']]

Here's the step-by-step breakdown:

  1. For the first iteration, j is 'd'. The inner list comprehension creates the list ['ad', 'bd', 'cd'].
  2. For the second iteration, j is 'e'. The inner list comprehension creates the list ['ae', 'be', 'ce'].
  3. For the third iteration, j is 'f'. The inner list comprehension creates the list ['af', 'bf', 'cf'].

These lists are collected into the outer list, resulting in the final output.

This problem has been solved

Solution 3

The output of the given Python code snippet will be a list of lists. Here's how it works:

  1. The outer list comprehension for j in "def" iterates over each character in the string "def". For each iteration, it creates a new list using the inner list comprehension.

  2. The inner list comprehension for i in "abc" iterates over each character in the string "abc". For each iteration, it appends the result of i+j to the current list.

  3. i+j concatenates the current characters from the strings "abc" and "def".

So, the output will be:

[['ad', 'bd', 'cd'], ['ae', 'be', 'ce'], ['af', 'bf', 'cf']]

In the first inner list, 'd' is added to each character in "abc", resulting in ['ad', 'bd', 'cd']. The same process is repeated for 'e' and 'f'.

This problem has been solved

Similar Questions

What will be the output of the following Python code snippet?print([[i+j for i in "abc"] for j in "def"])[‘da’, ‘ea’, ‘fa’, ‘db’, ‘eb’, ‘fb’, ‘dc’, ‘ec’, ‘fc’][[‘ad’, ‘bd’, ‘cd’], [‘ae’, ‘be’, ‘ce’], [‘af’, ‘bf’, ‘cf’]][[‘da’, ‘db’, ‘dc’], [‘ea’, ‘eb’, ‘ec’], [‘fa’, ‘fb’, ‘fc’]][‘ad’, ‘ae’, ‘af’, ‘bd’, ‘be’, ‘bf’, ‘cd’, ‘ce’, ‘cf’]

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