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What will be the output of the following Python code snippet?print([[i+j for i in "abc"] for j in "def"])[‘da’, ‘ea’, ‘fa’, ‘db’, ‘eb’, ‘fb’, ‘dc’, ‘ec’, ‘fc’][[‘ad’, ‘bd’, ‘cd’], [‘ae’, ‘be’, ‘ce’], [‘af’, ‘bf’, ‘cf’]][[‘da’, ‘db’, ‘dc’], [‘ea’, ‘eb’, ‘ec’], [‘fa’, ‘fb’, ‘fc’]][‘ad’, ‘ae’, ‘af’, ‘bd’, ‘be’, ‘bf’, ‘cd’, ‘ce’, ‘cf’]

Question

What will be the output of the following Python code snippet?print([[i+j for i in "abc"] for j in "def"])[‘da’, ‘ea’, ‘fa’, ‘db’, ‘eb’, ‘fb’, ‘dc’, ‘ec’, ‘fc’][[‘ad’, ‘bd’, ‘cd’], [‘ae’, ‘be’, ‘ce’], [‘af’, ‘bf’, ‘cf’]][[‘da’, ‘db’, ‘dc’], [‘ea’, ‘eb’, ‘ec’], [‘fa’, ‘fb’, ‘fc’]][‘ad’, ‘ae’, ‘af’, ‘bd’, ‘be’, ‘bf’, ‘cd’, ‘ce’, ‘cf’]

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Solution 1

The output of the given Python code snippet will be:

[['ad', 'bd', 'cd'], ['ae', 'be', 'ce'], ['af', 'bf', 'cf']]

Here's the step-by-step explanation:

  1. The outer list comprehension for j in "def" iterates over each character in the string "def".

  2. For each character j in "def", the inner list comprehension for i in "abc" creates a new list. It iterates over each character i in the string "abc".

  3. For each character i in "abc", it concatenates i and j (in that order) to form a new string.

  4. This new string is added to the inner list.

  5. Once all characters in "abc" have been processed, the inner list is complete and is added to the outer list.

  6. This process repeats for each character in "def", resulting in a list of lists.

So, the final output is a list of lists, where each inner list contains the concatenations of the characters in "abc" with a single character from "def".

This problem has been solved

Solution 2

The output of the given Python code snippet will be:

[['ad', 'bd', 'cd'], ['ae', 'be', 'ce'], ['af', 'bf', 'cf']]

Here's the step by step explanation:

  1. The outer list comprehension for j in "def" is executed first. It iterates over each character in the string "def".

  2. For each iteration of j, the inner list comprehension for i in "abc" is executed. It iterates over each character in the string "abc".

  3. In each iteration of i, the expression i+j is evaluated, which concatenates the characters i and j.

  4. The result of the inner list comprehension is a list of these concatenated strings for each character in "abc". This results in a list like ['ad', 'bd', 'cd'] for the first iteration of j.

  5. The outer list comprehension collects these lists into a larger list, resulting in the final output [['ad', 'bd', 'cd'], ['ae', 'be', 'ce'], ['af', 'bf', 'cf']].

This problem has been solved

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