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What will be the output of the following Python code?def foo(fname, val): print(fname(val))foo(max, [1, 2, 3])foo(min, [1, 2, 3])

Question

What will be the output of the following Python code?def foo(fname, val): print(fname(val))foo(max, [1, 2, 3])foo(min, [1, 2, 3])

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Solution 1

The output of the Python code will be:

3 1

Explanation:

The function foo takes two arguments: a function fname and a list val.

In the first call to foo, max is passed as fname and [1, 2, 3] as val. The max function returns the maximum value in the list, which is 3. This value is then printed.

In the second call to foo, min is passed as fname and [1, 2, 3] as val. The min function returns the minimum value in the list, which is 1. This value is then printed.

This problem has been solved

Solution 2

The output of the Python code will be:

3 1

Explanation:

The function foo takes two arguments: a function fname and a list val.

In the first call to foo, max is passed as fname and [1, 2, 3] as val. The max function returns the maximum value in the list, which is 3. This value is then printed.

In the second call to foo, min is passed as fname and [1, 2, 3] as val. The min function returns the minimum value in the list, which is 1. This value is then printed.

This problem has been solved

Solution 3

The given Python code defines a function foo that takes two arguments: a function fname and a list val. It then prints the result of applying fname to val.

The function foo is called twice. The first time, max is passed as fname and [1, 2, 3] as val. The max function returns the maximum value in a list, so max([1, 2, 3]) returns 3. Therefore, 3 is printed.

The second time, min is passed as fname and [1, 2, 3] as val. The min function returns the minimum value in a list, so min([1, 2, 3]) returns 1. Therefore, 1 is printed.

So, the output of the code will be:

3
1

This problem has been solved

Solution 4

The output of the Python code will be:

3 1

Explanation:

The function foo takes two arguments: a function fname and a list val.

In the first call to foo, max is passed as fname and [1, 2, 3] as val. The max function returns the maximum value in the list, which is 3. This value is then printed.

In the second call to foo, min is passed as fname and [1, 2, 3] as val. The min function returns the minimum value in the list, which is 1. This value is then printed.

This problem has been solved

Solution 5

The output of the Python code will be:

3 1

Explanation:

The function foo takes two arguments: a function fname and a list val.

In the first call to foo, max is passed as fname and [1, 2, 3] as val. The max function returns the maximum value in the list, which is 3. This value is then printed.

In the second call to foo, min is passed as fname and [1, 2, 3] as val. The min function returns the minimum value in the list, which is 1. This value is then printed.

This problem has been solved

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1/3

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