902.34 grams of Ba3(PO3)2   =  ____________________________  molecules Ba3(PO3)2 Remember that there are 6.02 x 1023 molecules in a mole.Group of answer choices9.54 x 1023 molecules8.91 x 1023  molecules5.43 x1026 molecules3.42 x 1026 molecules

To answer this question, we first need to find the molar mass of Ba3(PO3)2.

1. Calculate the molar mass of Ba3(PO3)2:

   • Barium (Ba) has a molar mass of about 137.33 g/mol. Since there are 3 Ba atoms, the total mass of Ba is 3*137.33 = 411.99 g/mol.
   • Phosphorus (P) has a molar mass of about 30.97 g/mol. Since there are 2 P atoms in each PO3, and 2 PO3 in the formula, the total mass of P is 2230.97 = 123.88 g/mol.
   • Oxygen (O) has a molar mass of about 16.00 g/mol. Since there are 3 O atoms in each PO3, and 2 PO3 in the formula, the total mass of O is 2316.00 = 192.00 g/mol.
   • Add these up to find the molar mass of Ba3(PO3)2: 411.99 + 123.88 + 192.00 = 727.87 g/mol.

2. Convert grams to moles using the molar mass:

   • We have 902.34 grams of Ba3(PO3)2 and we know that 1 mole of Ba3(PO3)2 is 727.87 grams. So, the number of moles is 902.34 / 727.87 = 1.24 moles.

3. Convert moles to molecules using Avogadro's number:

   • We know that 1 mole contains 6.02 x 10^23 molecules. So, the number of molecules is 1.24 * 6.02 x 10^23 = 7.46 x 10^23 molecules.

So, the closest answer to this would be 9.54 x 10^23 molecules.