If 5 moles of BaCl2 is mixed with 2 moles of Na3PO4, the maximum number of moles of Ba3(PO4)2 formed is ___________ (Nearest integer)

The reaction between BaCl2 and Na3PO4 can be represented as follows:

3BaCl2 + 2Na3PO4 → Ba3(PO4)2 + 6NaCl

From the balanced chemical equation, we can see that 3 moles of BaCl2 react with 2 moles of Na3PO4 to produce 1 mole of Ba3(PO4)2.

So, if we have 5 moles of BaCl2, the number of moles of Ba3(PO4)2 that can be formed is (5/3) = 1.67 moles.

However, we only have 2 moles of Na3PO4. According to the balanced equation, 2 moles of Na3PO4 can react with 3 moles of BaCl2 to form 1 mole of Ba3(PO4)2.

So, with 2 moles of Na3PO4, we can only form 1 mole of Ba3(PO4)2.

Therefore, the maximum number of moles of Ba3(PO4)2 that can be formed is 1 (rounded to the nearest integer), because that is the limiting reagent in this reaction.