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5. Match the number of moles of each compound to its equivalent mass in grams.Moles of CompoundMass in Grams2.5 moles Ca3(PO4)22.5 moles P4O104 moles Na2SO45 moles NH4NO3 400.22 g568.20 g709.70 g775.45 g

Question

  1. Match the number of moles of each compound to its equivalent mass in grams.Moles of CompoundMass in Grams2.5 moles Ca3(PO4)22.5 moles P4O104 moles Na2SO45 moles NH4NO3 400.22 g568.20 g709.70 g775.45 g
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Solution

To match the number of moles of each compound to its equivalent mass in grams, we first need to calculate the molar mass of each compound. The molar mass is the mass of one mole of a substance, usually expressed in grams or kilograms.

  1. Ca3(PO4)2: The molar mass is calculated as follows: (340.08 for Ca) + (2(3*1.007 + 15.999 for PO4)) = 310.18 g/mol. For 2.5 moles, the mass is 2.5 * 310.18 = 775.45 g.

  2. P4O10: The molar mass is calculated as follows: (430.974 for P) + (1015.999 for O) = 283.89 g/mol. For 2.5 moles, the mass is 2.5 * 283.89 = 709.725 g, which can be approximated to 709.70 g.

  3. Na2SO4: The molar mass is calculated as follows: (222.990 for Na) + (32.06 for S) + (415.999 for O) = 142.04 g/mol. For 4 moles, the mass is 4 * 142.04 = 568.16 g, which can be approximated to 568.20 g.

  4. NH4NO3: The molar mass is calculated as follows: (21.007 for H) + 14.007 for N + (315.999 for O) + 1.007 for H + 14.007 for N = 80.043 g/mol. For 5 moles, the mass is 5 * 80.043 = 400.215 g, which can be approximated to 400.22 g.

So, the matches are:

  • 2.5 moles Ca3(PO4)2 = 775.45 g
  • 2.5 moles P4O10 = 709.70 g
  • 4 moles Na2SO4 = 568.20 g
  • 5 moles NH4NO3 = 400.22 g

This problem has been solved

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