Calculate the molecular mass of  Ba3(PO3)2

To calculate the molecular mass of Ba3(PO3)2, you need to know the atomic masses of the elements involved and then add them up accordingly.

1. The atomic mass of Barium (Ba) is approximately 137.33 g/mol. Since there are 3 Ba atoms in the formula, the total mass contributed by Ba is 137.33 g/mol * 3 = 411.99 g/mol.

2. The atomic mass of Phosphorus (P) is approximately 30.97 g/mol. Since there are 2 P atoms in each PO3 and 2 PO3 in the formula, the total mass contributed by P is 30.97 g/mol * 2 * 2 = 123.88 g/mol.

3. The atomic mass of Oxygen (O) is approximately 16.00 g/mol. Since there are 3 O atoms in each PO3 and 2 PO3 in the formula, the total mass contributed by O is 16.00 g/mol * 3 * 2 = 96.00 g/mol.

4. Add up the masses contributed by each element to get the molecular mass of Ba3(PO3)2: 411.99 g/mol + 123.88 g/mol + 96.00 g/mol = 631.87 g/mol.

So, the molecular mass of Ba3(PO3)2 is approximately 631.87 g/mol.