The distance between two points in a plane with coordinates (x1, y1) and (x2, y2) is given by the formula:

d = sqrt[(x2-x1)² + (y2-y1)²]

In this case, the coordinates of the two points are (-12, -8) and (-12, 16). So, x1 = -12, y1 = -8, x2 = -12, and y2 = 16.

Substituting these values into the formula, we get:

d = sqrt[(-12 - (-12))² + (16 - (-8))²]
d = sqrt[(0)² + (24)²]
d = sqrt[0 + 576]
d = sqrt[576]

Therefore, the distance between the points (-12, -8) and (-12, 16) is sqrt[576] = 24 units.

Question

The distance between two points in a plane with coordinates (x1, y1) and (x2, y2) is given by the formula:

d = sqrt[(x2-x1)² + (y2-y1)²]

In this case, the coordinates of the two points are (-12, -8) and (-12, 16). So, x1 = -12, y1 = -8, x2 = -12, and y2 = 16.

Substituting these values into the formula, we get:

d = sqrt[(-12 - (-12))² + (16 - (-8))²]
d = sqrt[(0)² + (24)²]
d = sqrt[0 + 576]
d = sqrt[576]

Therefore, the distance between the points (-12, -8) and (-12, 16) is sqrt[576] = 24 units.

Knowee AI · Accepted Answer

The distance between two points in a plane with coordinates (x1, y1) and (x2, y2) is given by the formula:

d = sqrt[(x2-x1)² + (y2-y1)²]

In this case, the coordinates of the two points are (-12, -8) and (-12, 16). So, x1 = -12, y1 = -8, x2 = -12, and y2 = 16.

Substituting these values into the formula, we get:

d = sqrt[(-12 - (-12))² + (16 - (-8))²]
d = sqrt[(0)² + (24)²]
d = sqrt[0 + 576]
d = sqrt[576]

Therefore, the distance between the points (-12, -8) and (-12, 16) is sqrt[576] = 24 units.

Find the distance between the points (–12,–8) and (–12,16). units