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Find the distance between the points (–9,8) and (–9,–5.7). unitsSubmit

Question

Find the distance between the points (–9,8) and (–9,–5.7). unitsSubmit

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Solution

Para encontrar la distancia entre los puntos (–9, 8) y (–9, –5.7), utilizamos la fórmula de la distancia entre dos puntos en un plano cartesiano. La fórmula es:

d=(x2x1)2+(y2y1)2 d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Dado que los puntos son (–9, 8) y (–9, –5.7), podemos identificar las coordenadas como: (x1,y1)=(9,8) (x_1, y_1) = (–9, 8) (x2,y2)=(9,5.7) (x_2, y_2) = (–9, –5.7)

Sustituimos estos valores en la fórmula:

d=(9(9))2+(5.78)2 d = \sqrt{(–9 - (–9))^2 + (–5.7 - 8)^2}

Simplificamos dentro de la raíz:

d=(0)2+(5.78)2 d = \sqrt{(0)^2 + (–5.7 - 8)^2} d=0+(13.7)2 d = \sqrt{0 + (–13.7)^2} d=0+187.69 d = \sqrt{0 + 187.69} d=187.69 d = \sqrt{187.69} d13.7 d \approx 13.7

Por lo tanto, la distancia entre los puntos (–9, 8) y (–9, –5.7) es aproximadamente 13.7 unidades.

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