Solve for z.z2+24z+23=0Write each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas.
Question
Solve for z.z2+24z+23=0Write each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas.
Solution
To solve the quadratic equation z^2 + 24z + 23 = 0, we can use the quadratic formula, which is given by:
z = [-b ± sqrt(b^2 - 4ac)] / (2a)
Here, a = 1 (the coefficient of z^2), b = 24 (the coefficient of z), and c = 23 (the constant term).
First, calculate the discriminant, which is b^2 - 4ac:
Discriminant = (24)^2 - 4123 = 576 - 92 = 484
Since the discriminant is positive, there are two distinct real roots for this equation.
Now, substitute a, b, and the discriminant into the quadratic formula to find the solutions for z:
z = [-24 ± sqrt(484)] / (2*1) z = [-24 ± 22] / 2
This gives us two solutions:
z = (-24 + 22) / 2 = -2/2 = -1 z = (-24 - 22) / 2 = -46/2 = -23
So, the solutions to the equation z^2 + 24z + 23 = 0 are z = -1 and z = -23.
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