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Solve for y.y2–2y–24=0Write each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas.

Question

Solve for y.y2–2y–24=0Write each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas.

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Solution

The given equation is a quadratic equation. The general form of a quadratic equation is ax^2 + bx + c = 0. The solutions of a quadratic equation can be found using the quadratic formula, which is x = [-b ± sqrt(b^2 - 4ac)] / 2a.

Here, the equation is y^2 - 2y - 24 = 0. Comparing this with the general form, we get a = 1, b = -2, and c = -24.

Substituting these values into the quadratic formula, we get:

y = [2 ± sqrt((-2)^2 - 41(-24))] / 2*1 = [2 ± sqrt(4 + 96)] / 2 = [2 ± sqrt(100)] / 2 = [2 ± 10] / 2 = 2/2, 12/2 = 1, 6

So, the solutions of the given equation are y = 1 and y = 6.

This problem has been solved

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