Solve for d.d2+10d–24=0Write each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas.
Question
Solve for d.d2+10d–24=0Write each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas.
Solution
The given equation is a quadratic equation in the form of ax^2 + bx + c = 0, where a = 1, b = 10, and c = -24.
The solutions for x (in this case d) in a quadratic equation can be found using the quadratic formula, which is:
x = [-b ± sqrt(b^2 - 4ac)] / 2a
Substituting the values of a, b, and c into the formula, we get:
d = [-10 ± sqrt((10)^2 - 41(-24))] / 2*1 d = [-10 ± sqrt(100 + 96)] / 2 d = [-10 ± sqrt(196)] / 2 d = [-10 ± 14] / 2
This gives us two solutions:
d = (-10 + 14) / 2 = 4/2 = 2 d = (-10 - 14) / 2 = -24/2 = -12
So, the solutions for the equation d^2 + 10d - 24 = 0 are d = 2 and d = -12.
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