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Solve for d.d2+10d–24=0Write each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas.

Question

Solve for d.d2+10d–24=0Write each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas.

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Solution

The given equation is a quadratic equation in the form of ax^2 + bx + c = 0, where a = 1, b = 10, and c = -24.

The solutions for x (in this case d) in a quadratic equation can be found using the quadratic formula, which is:

x = [-b ± sqrt(b^2 - 4ac)] / 2a

Substituting the values of a, b, and c into the formula, we get:

d = [-10 ± sqrt((10)^2 - 41(-24))] / 2*1 d = [-10 ± sqrt(100 + 96)] / 2 d = [-10 ± sqrt(196)] / 2 d = [-10 ± 14] / 2

This gives us two solutions:

d = (-10 + 14) / 2 = 4/2 = 2 d = (-10 - 14) / 2 = -24/2 = -12

So, the solutions for the equation d^2 + 10d - 24 = 0 are d = 2 and d = -12.

This problem has been solved

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