This is a quadratic equation in the form of ax^2 + bx + c = 0, where a = 1, b = -34, and c = 0.

The solutions to a quadratic equation are given by the formula x = [-b ± sqrt(b^2 - 4ac)] / 2a.

Substituting the values of a, b, and c into the formula, we get:

d = [34 ± sqrt((-34)^2 - 4*1*0)] / 2*1
d = [34 ± sqrt(1156)] / 2
d = [34 ± 34] / 2

So the solutions are d = 34/2 = 17 and d = 0/2 = 0.

Therefore, the solutions to the equation d^2 - 34d = 0 are d = 0 and d = 17.

Question

This is a quadratic equation in the form of ax^2 + bx + c = 0, where a = 1, b = -34, and c = 0.

The solutions to a quadratic equation are given by the formula x = [-b ± sqrt(b^2 - 4ac)] / 2a.

Substituting the values of a, b, and c into the formula, we get:

d = [34 ± sqrt((-34)^2 - 4*1*0)] / 2*1
d = [34 ± sqrt(1156)] / 2
d = [34 ± 34] / 2

So the solutions are d = 34/2 = 17 and d = 0/2 = 0.

Therefore, the solutions to the equation d^2 - 34d = 0 are d = 0 and d = 17.

Knowee AI · Accepted Answer

This is a quadratic equation in the form of ax^2 + bx + c = 0, where a = 1, b = -34, and c = 0.

The solutions to a quadratic equation are given by the formula x = [-b ± sqrt(b^2 - 4ac)] / 2a.

Substituting the values of a, b, and c into the formula, we get:

d = [34 ± sqrt((-34)^2 - 4*1*0)] / 2*1
d = [34 ± sqrt(1156)] / 2
d = [34 ± 34] / 2

So the solutions are d = 34/2 = 17 and d = 0/2 = 0.

Therefore, the solutions to the equation d^2 - 34d = 0 are d = 0 and d = 17.

Solve for d.d2–34d=0Write each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas.