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A mixture of 729 ml contains milk and water in the ratio of 7:2. Calculate the amount of water that must be added to obtain a new mixture with ratio 7:3?502381None of the above

Question

A mixture of 729 ml contains milk and water in the ratio of 7:2. Calculate the amount of water that must be added to obtain a new mixture with ratio 7:3?502381None of the above

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Solution

The initial volume of the mixture is 729 ml, with a milk to water ratio of 7:2.

Step 1: Calculate the initial volume of milk and water The total parts of the mixture = 7 parts milk + 2 parts water = 9 parts So, 1 part of the mixture = 729 ml / 9 = 81 ml

The volume of milk = 7 parts * 81 ml/part = 567 ml The volume of water = 2 parts * 81 ml/part = 162 ml

Step 2: Calculate the amount of water to be added to get a 7:3 milk to water ratio In the new mixture, the volume of milk remains the same (567 ml), but the ratio changes to 7:3.

So, 7 parts represent 567 ml, which means 1 part represents 567 ml / 7 = 81 ml

Therefore, 3 parts (the new ratio for water) would represent 3 * 81 ml = 243 ml

Step 3: Calculate the difference in the volume of water The amount of water that needs to be added = New volume of water - initial volume of water = 243 ml - 162 ml = 81 ml

So, 81 ml of water must be added to the mixture to obtain a new mixture with a milk to water ratio of 7:3.

This problem has been solved

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