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A vessel contains 630 ml of mixture of milk and water in the ratio 7 : 2. How much water must be added to make the ratio 7 : 3?Options70 ml80 ml50 ml60 ml

Question

A vessel contains 630 ml of mixture of milk and water in the ratio 7 : 2. How much water must be added to make the ratio 7 : 3?Options70 ml80 ml50 ml60 ml

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Solution

To solve this problem, we first need to determine the initial quantities of milk and water in the mixture.

  1. The total ratio of milk to water is 7:2, which adds up to 9 parts.
  2. Each part of the mixture is therefore 630 ml / 9 = 70 ml.
  3. The quantity of milk is 7 parts * 70 ml/part = 490 ml.
  4. The quantity of water is 2 parts * 70 ml/part = 140 ml.

Next, we need to find out how much water must be added to make the ratio 7:3.

  1. If the quantity of milk remains constant at 490 ml, and the ratio of milk to water is 7:3, then the total ratio is 10 parts.
  2. Each part of the new mixture is therefore 490 ml / 7 = 70 ml.
  3. The quantity of water in the new mixture should be 3 parts * 70 ml/part = 210 ml.
  4. Therefore, the amount of water that must be added is 210 ml - 140 ml = 70 ml.

So, the correct answer is 70 ml.

This problem has been solved

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