Which of these is a point-slope equation of the line that is perpendicular toy – 3 = 4(x – 10) and passes through (–3, 7)?A.y – 7 = –1441 (x + 3)B.y + 7 = 4(x – 3)C.y + 7 = –1441 (x – 3)D.y – 7 = –4(x + 3)SUBMITarrow_backPREVIOUS
Question
Which of these is a point-slope equation of the line that is perpendicular toy – 3 = 4(x – 10) and passes through (–3, 7)?A.y – 7 = –1441 (x + 3)B.y + 7 = 4(x – 3)C.y + 7 = –1441 (x – 3)D.y – 7 = –4(x + 3)SUBMITarrow_backPREVIOUS
Solution
The equation of the line given is in point-slope form, y - y1 = m(x - x1), where m is the slope of the line and (x1, y1) is a point on the line.
The slope of the given line is 4. The slope of a line perpendicular to this line would be the negative reciprocal of 4, which is -1/4.
The point through which the perpendicular line passes is (-3, 7).
Substituting these values into the point-slope form of the equation gives:
y - 7 = -1/4(x + 3)
Multiplying through by 4 to get rid of the fraction gives:
4(y - 7) = -(x + 3)
This simplifies to:
4y - 28 = -x - 3
Rearranging terms gives:
4y = x + 31
This is the equation of the line that is perpendicular to the given line and passes through the point (-3, 7).
However, none of the given options match this equation. There may be a mistake in the question or the answer choices.
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