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A line passes through the points (–3,–7) and (6,–7). Write its equation in slope-intercept form.

Question

A line passes through the points (–3,–7) and (6,–7). Write its equation in slope-intercept form.

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Solution

The slope-intercept form of a line is given by y = mx + b, where m is the slope and b is the y-intercept.

Step 1: Find the slope (m) The slope of a line passing through the points (x1, y1) and (x2, y2) is given by (y2 - y1) / (x2 - x1).

For the points (–3,–7) and (6,–7), the slope m = (–7 - (–7)) / (6 - (–3)) = 0 / 9 = 0.

Step 2: Find the y-intercept (b) Since the line passes through the points (–3,–7) and (6,–7), we know that the y-coordinate is the same for both points, which is -7. This means that the line crosses the y-axis at -7. So, b = -7.

Step 3: Write the equation of the line Substitute m = 0 and b = -7 into the equation y = mx + b to get the equation of the line: y = 0x - 7.

Simplify this to get the final equation of the line: y = -7.

This problem has been solved

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