What is the equation of a line that is perpendicular to and passes through the point (6, 8)?A.B.C.D.SUBMITarrow_backPREVIOUS

It seems like there's a mistake in your question as the line to which the new line should be perpendicular is not mentioned. However, I can explain the process to find the equation of a line that is perpendicular to a given line and passes through a specific point.

1. First, you need to know the slope of the given line. The slope of a line in the plane containing the x and y axes is generally represented by the letter m.

2. The slope of the line perpendicular to the given line is the negative reciprocal of the slope of the given line. If the slope of the given line is m, then the slope of the line perpendicular to it is -1/m.

3. Once you have the slope of the perpendicular line, you can use the point-slope form of the equation of a line to find its equation. The point-slope form is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line.

4. Substitute the slope of the perpendicular line and the coordinates of the given point into the point-slope form to find the equation of the line.

Please provide the equation of the line to which the new line should be perpendicular so I can help you find the specific equation.

The question seems to be incomplete. You mentioned that the line is perpendicular to another line, but you didn't provide the equation of that line. Could you please provide the equation of the line to which the new line is perpendicular?