The air pressure inside a tyre is 200 kPa. Calculate the force which this air will exert on the inside surface of the tyre if it has a surface area of 0.1 m2.20,000 N2,000,000 N2,000 N20 N2A given amount of gas is held inside a container. The volume of the container can be changed using a movable piston. Which of the following will cause the pressure which the gas exerts on the walls of the container to decrease?Pumping more gas into (increasing the number of particles inside) the containerHeating the gasPulling the piston outwards (so that the volume of the container increases)Pushing the piston inwards (so that the volume of the container decreases)3A submarine experiences a pressure of 100,000 Pa at the surface of the sea. Calculate the total pressure which it will experience when it descends to a depth of 100 metres. The density of seawater is approximately 1,030 kg/m3, and the value of g is 10 N/kg.1,030,000 Pa110,300 Pa1,130,000 Pa10,300 Pa4A boy is swimming 5 metres below the surface of a swimming pool. How will the pressure exerted on him change when he swims back to the surface? The density of the water in the pool is approximately 1000 kg/m3 and the value of g is 10 N/kg.The pressure will decrease by 500 PaThe pressure will increase by 50,000 PaThe pressure will increase by 500 PaThe pressure will decrease by 50,000 Pa5An object is described as having neutral buoyancy. Which of the following statements do NOT apply to it?It will be in a state of equilibriumIt is less dense than the fluid in which it is submergedThe pressure exerted on it will increase with depthIts weight is equal in magnitude to the upthrust force acting on it6Which of the following describes how atmospheric pressure (the pressure of the air that makes up our atmosphere) changes with altitude?It increases as altitude increasesIt remains constantWhether it increases, decreases or stays the same depends on local weather conditionsIt decreases as altitude increases
Question
The air pressure inside a tyre is 200 kPa. Calculate the force which this air will exert on the inside surface of the tyre if it has a surface area of 0.1 m2.20,000 N2,000,000 N2,000 N20 N2A given amount of gas is held inside a container. The volume of the container can be changed using a movable piston. Which of the following will cause the pressure which the gas exerts on the walls of the container to decrease?Pumping more gas into (increasing the number of particles inside) the containerHeating the gasPulling the piston outwards (so that the volume of the container increases)Pushing the piston inwards (so that the volume of the container decreases)3A submarine experiences a pressure of 100,000 Pa at the surface of the sea. Calculate the total pressure which it will experience when it descends to a depth of 100 metres. The density of seawater is approximately 1,030 kg/m3, and the value of g is 10 N/kg.1,030,000 Pa110,300 Pa1,130,000 Pa10,300 Pa4A boy is swimming 5 metres below the surface of a swimming pool. How will the pressure exerted on him change when he swims back to the surface? The density of the water in the pool is approximately 1000 kg/m3 and the value of g is 10 N/kg.The pressure will decrease by 500 PaThe pressure will increase by 50,000 PaThe pressure will increase by 500 PaThe pressure will decrease by 50,000 Pa5An object is described as having neutral buoyancy. Which of the following statements do NOT apply to it?It will be in a state of equilibriumIt is less dense than the fluid in which it is submergedThe pressure exerted on it will increase with depthIts weight is equal in magnitude to the upthrust force acting on it6Which of the following describes how atmospheric pressure (the pressure of the air that makes up our atmosphere) changes with altitude?It increases as altitude increasesIt remains constantWhether it increases, decreases or stays the same depends on local weather conditionsIt decreases as altitude increases
Solution
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The force exerted by the air inside the tyre can be calculated using the formula: Force = Pressure x Area. Substituting the given values, we get: Force = 200,000 Pa x 0.1 m^2 = 20,000 N.
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The pressure of a gas is inversely proportional to its volume, given the temperature and the number of particles are constant. Therefore, pulling the piston outwards (increasing the volume of the container) will cause the pressure exerted by the gas on the walls of the container to decrease.
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The total pressure experienced by a submarine at a certain depth is the sum of the atmospheric pressure and the pressure due to the water above it. The pressure due to the water can be calculated using the formula: Pressure = Density x g x Height. Substituting the given values, we get: Pressure = 1,030 kg/m^3 x 10 N/kg x 100 m = 1,030,000 Pa. Adding the atmospheric pressure (100,000 Pa), the total pressure is 1,130,000 Pa.
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The pressure exerted on a swimmer changes with depth according to the formula: Pressure = Density x g x Height. Therefore, when the boy swims back to the surface, the pressure will decrease by: 1000 kg/m^3 x 10 N/kg x 5 m = 50,000 Pa.
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An object with neutral buoyancy is in a state of equilibrium and its weight is equal in magnitude to the upthrust force acting on it. However, it is not necessarily less dense than the fluid in which it is submerged. Also, the pressure exerted on it will indeed increase with depth.
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Atmospheric pressure decreases as altitude increases. This is because the density of air (and therefore the weight of the air above a given point) decreases with altitude.
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