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e place ourselves withinthe setup of the Black-Scholes market model M = (B, S) with a unique martingalemeasure ˜P. Consider a European contingent claim Y with maturity T and thefollowing payoffY = γST − max (ST , L)where L = erT S0 and γ > 0 is a real number. We take for granted the Black-Scholespricing formulae for the call and put options.(a) Sketch the profile of the payoff Y as a function of the stock price ST at time Tand show that Y admits the representation Y = γST − CT (L) − L where CT (L)denotes the payoff at time T of the European call option with strike L.

Question

e place ourselves withinthe setup of the Black-Scholes market model M = (B, S) with a unique martingalemeasure ˜P. Consider a European contingent claim Y with maturity T and thefollowing payoffY = γST − max (ST , L)where L = erT S0 and γ > 0 is a real number. We take for granted the Black-Scholespricing formulae for the call and put options.(a) Sketch the profile of the payoff Y as a function of the stock price ST at time Tand show that Y admits the representation Y = γST − CT (L) − L where CT (L)denotes the payoff at time T of the European call option with strike L.

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Solution

The payoff Y is given by Y = γST - max(ST, L). This can be rewritten as Y = γST - ST if ST > L and Y = γST - L if ST ≤ L.

The profile of the payoff Y as a function of the stock price ST at time T can be sketched as follows:

  1. If ST > L, the payoff Y = γST - ST. This is a straight line with slope (γ - 1) and intercept 0. The payoff decreases as ST increases.

  2. If ST ≤ L, the payoff Y = γST - L. This is a straight line with slope γ and intercept -L. The payoff increases as ST increases.

The representation Y = γST - CT(L) - L can be obtained by noting that CT(L) is the payoff of a European call option with strike L. This means that CT(L) = max(ST - L, 0).

Therefore, if ST > L, then CT(L) = ST - L and Y = γST - (ST - L) - L = γST - ST = (γ - 1)ST.

If ST ≤ L, then CT(L) = 0 and Y = γST - 0 - L = γST - L.

So, the representation Y = γST - CT(L) - L holds for all ST.

This problem has been solved

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