What does the following code snippet do?123456789#include <stdio.h>#include <string.h>int main() { char str[] = "abc"; for (int i = 0; str[i] != '\0'; ++i) str[i] = str[i] + 1; return 0;}

This C code snippet defines a string "abc" and then increments each character in the string by one. Here's a step-by-step breakdown:

1. #include <stdio.h> and #include <string.h>: These are preprocessor directives that include the standard input/output library and the string library in the program.

2. int main() {: This is the main function where the program execution begins.

3. char str[] = "abc";: This line declares a string str and initializes it with the value "abc".

4. for (int i = 0; str[i] != '\0'; ++i): This is a for loop that iterates over each character in the string until it encounters the null character ('\0'), which signifies the end of the string.

5. str[i] = str[i] + 1;: Inside the loop, each character in the string is incremented by one. This is done by adding 1 to the ASCII value of the current character, effectively shifting it one place forward in the ASCII table. For example, 'a' becomes 'b', 'b' becomes 'c', and so on.

6. return 0;: This line signifies the successful termination of the program.

However, it's worth noting that the modified string is not printed or stored anywhere, so you wouldn't see any output from running this code as it is. If you want to see the result, you should add a line to print the string, like printf("%s", str);, before the return 0; line.