1.1-6. If P (A) = 0.4, P (B) = 0.5, and P (A ∩ B) = 0.3, find(a) P (A ∩ B)(b) P (A ∪ B′)(c) P (A′ ∪ B′)

1. 1.1-6. If P (A) = 0.4, P (B) = 0.5, and P (A ∩ B) = 0.3, find(a) P (A ∩ B)(b) P (A ∪ B′)(c) P (A′ ∪ B′)2. 1.1-9 Roll a fair six-sided die three times. Let A1 = {1 or 2 on the first roll}, A2 ={3 or 4 on the second roll}, A3 = {5 or 6 on the third roll}. It is given that P (Ai) = 1/3,i = 1, 2, 3; P (Ai ∪ Aj ) = (1/3)2, i̸ = j; and P (A1 ∪ A2 ∪ A3) = (1/3)3.(a) Use Theorem 1.1-6 (from the textbook) to find P (A1 ∪ A2 ∪ A3)(b) Given that P (A′1 ∩ A′2 ∩ A′3) = P (A′1)P (A′2)P (A′3) (which is due to independence,a concept that will be covered later), show that P (A1 ∪ A2 ∪ A3) = 1 − (1 − 1/3)3.3. 1.1-10. Prove Theorem 1.1-61

If A and B are independent events with P(A) = 0.02 and P(B) = 0.6, then P(A ∪ B) =Question 4Select one:a.0.62b.0.60c.0.71d.0.8

If P(A) = 0.60, P(B) = 0.58, and P(A ∪ B) = 0.70, then P(A ∩ B) is:Group of answer choices0.58.0.48.0.60.0.70.

Let A𝐴 and B𝐵 are two events and P(A′)=0⋅3𝑃𝐴'=0·3, P(B)=0⋅4, P(A∩B′)=0⋅5𝑃𝐵=0·4, 𝑃𝐴∩𝐵'=0·5 then P(A∪B′)𝑃𝐴∪𝐵' is:

P(A∩B)=P(A)P(B)