If A and B are independent events with P(A) = 0.02 and P(B) = 0.6, then P(A ∪ B) =Question 4Select one:a.0.62b.0.60c.0.71d.0.8
Question
If A and B are independent events with P(A) = 0.02 and P(B) = 0.6, then P(A ∪ B) =Question 4Select one:a.0.62b.0.60c.0.71d.0.8
Solution
The probability of either event A or event B occurring (P(A ∪ B)) can be found using the formula for the union of two independent events, which is P(A) + P(B) - P(A ∩ B).
Since A and B are independent, the probability of both A and B occurring (P(A ∩ B)) is simply P(A) * P(B).
So, P(A ∪ B) = P(A) + P(B) - P(A) * P(B).
Substituting the given values:
P(A ∪ B) = 0.02 + 0.6 - 0.02 * 0.6 = 0.62 - 0.012 = 0.608.
So, the answer closest to this is a. 0.62.
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