P(A) = 0.35, P(B) = 0.5 what is P(A∪B) if A and B are mutually excluded eventsQuestion 5Select one:a.0.85b.0.75c.0.15d.0.8
Question
P(A) = 0.35, P(B) = 0.5 what is P(A∪B) if A and B are mutually excluded eventsQuestion 5Select one:a.0.85b.0.75c.0.15d.0.8
Solution
If events A and B are mutually exclusive, it means that they cannot occur at the same time. In other words, the occurrence of one event excludes the occurrence of the other. Therefore, the probability of either event A or event B occurring (P(A∪B)) is simply the sum of their individual probabilities.
So, P(A∪B) = P(A) + P(B)
Substituting the given values:
P(A∪B) = 0.35 + 0.5 = 0.85
So, the answer is a. 0.85.
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