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1. 1.1-6. If P (A) = 0.4, P (B) = 0.5, and P (A ∩ B) = 0.3, find(a) P (A ∩ B)(b) P (A ∪ B′)(c) P (A′ ∪ B′)2. 1.1-9 Roll a fair six-sided die three times. Let A1 = {1 or 2 on the first roll}, A2 ={3 or 4 on the second roll}, A3 = {5 or 6 on the third roll}. It is given that P (Ai) = 1/3,i = 1, 2, 3; P (Ai ∪ Aj ) = (1/3)2, i̸ = j; and P (A1 ∪ A2 ∪ A3) = (1/3)3.(a) Use Theorem 1.1-6 (from the textbook) to find P (A1 ∪ A2 ∪ A3)(b) Given that P (A′1 ∩ A′2 ∩ A′3) = P (A′1)P (A′2)P (A′3) (which is due to independence,a concept that will be covered later), show that P (A1 ∪ A2 ∪ A3) = 1 − (1 − 1/3)3.3. 1.1-10. Prove Theorem 1.1-61

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  1. 1.1-6. If P (A) = 0.4, P (B) = 0.5, and P (A ∩ B) = 0.3, find(a) P (A ∩ B)(b) P (A ∪ B′)(c) P (A′ ∪ B′)2. 1.1-9 Roll a fair six-sided die three times. Let A1 = {1 or 2 on the first roll}, A2 ={3 or 4 on the second roll}, A3 = {5 or 6 on the third roll}. It is given that P (Ai) = 1/3,i = 1, 2, 3; P (Ai ∪ Aj ) = (1/3)2, i̸ = j; and P (A1 ∪ A2 ∪ A3) = (1/3)3.(a) Use Theorem 1.1-6 (from the textbook) to find P (A1 ∪ A2 ∪ A3)(b) Given that P (A′1 ∩ A′2 ∩ A′3) = P (A′1)P (A′2)P (A′3) (which is due to independence,a concept that will be covered later), show that P (A1 ∪ A2 ∪ A3) = 1 − (1 − 1/3)3.3. 1.1-10. Prove Theorem 1.1-61
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Roll a fair six-sided die three times. Let A1 = {1 or 2 on the first roll}, A2 ={3 or 4 on the second roll}, A3 = {5 or 6 on the third roll}. It is given that P (Ai) = 1/3,i = 1, 2, 3; P (Ai ∩ Aj ) = (1/3)2, i̸ = j; and P (A1 ∩ A2 ∩ A3) = (1/3)3.(a) Use Theorem 1.1-6 (from the textbook) to find P (A1 ∪ A2 ∪ A3)(b) Given that P (A′1 ∩ A′2 ∩ A′3) = P (A′1)P (A′2)P (A′3) (which is due to independence,a concept that will be covered later), show that P (A1 ∪ A2 ∪ A3) = 1 − (1 − 1/3)3.

1.1-6. If P (A) = 0.4, P (B) = 0.5, and P (A ∩ B) = 0.3, find(a) P (A ∪ B)(b) P (A ∩ B′)(c) P (A′ ∪ B′)

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