Given f, of, x, equals, minus, x, squared, minus, 2, x, plus, 3f(x)=−x 2 −2x+3, find f, of, 1f(1)
Question
Given f, of, x, equals, minus, x, squared, minus, 2, x, plus, 3f(x)=−x 2 −2x+3, find f, of, 1f(1)
Solution
To find the value of f(1), you need to substitute x = 1 into the function f(x) = -x^2 - 2x + 3.
So, f(1) = -(1)^2 - 2*(1) + 3 = -1 - 2 + 3 = 0
So, f(1) = 0.
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