Given f, of, x, equals, minus, 3, x, squared, plus, 6, x, plus, 1f(x)=−3x 2 +6x+1, find f, of, 6f(6)
Question
Given f, of, x, equals, minus, 3, x, squared, plus, 6, x, plus, 1f(x)=−3x 2 +6x+1, find f, of, 6f(6)
Solution
To find the value of f(6), you need to substitute x = 6 into the function f(x) = -3x^2 + 6x + 1.
Step 1: Substitute x = 6 into the function f(6) = -3(6)^2 + 6(6) + 1
Step 2: Simplify the equation f(6) = -3(36) + 36 + 1 f(6) = -108 + 36 + 1
Step 3: Add the numbers f(6) = -71
So, f(6) = -71.
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