Given f, of, x, equals, 3, x, squared, minus, x, plus, 2f(x)=3x 2 −x+2, find f, of, minus, 4f(−4)
Question
Given f, of, x, equals, 3, x, squared, minus, x, plus, 2f(x)=3x 2 −x+2, find f, of, minus, 4f(−4)
Solution 1
To find the value of f(-4), you need to substitute -4 in place of x in the function f(x) = 3x^2 - x + 2.
So, f(-4) = 3(-4)^2 - (-4) + 2
First, calculate the square of -4, which is 16.
So, f(-4) = 3*16 - (-4) + 2
Then, multiply 3 by 16, which is 48.
So, f(-4) = 48 - (-4) + 2
The minus sign before the 4 becomes a plus when you subtract a negative number.
So, f(-4) = 48 + 4 + 2
Finally, add 48, 4, and 2 together to get 54.
So, f(-4) = 54.
Solution 2
To find the value of f(-4), you need to substitute -4 in place of x in the function f(x) = 3x^2 - x + 2.
So, f(-4) = 3(-4)^2 - (-4) + 2
First, calculate the square of -4, which is 16.
So, f(-4) = 3*16 - (-4) + 2
Then, multiply 3 by 16, which is 48.
So, f(-4) = 48 - (-4) + 2
The minus sign before the -4 changes to a plus sign, so the equation becomes:
f(-4) = 48 + 4 + 2
Finally, add 48, 4, and 2 together to get 54.
So, f(-4) = 54.
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