A fighter jet accelerates at an average rate of 10.43 m/s2 and takes 6.90 sec to take off. If the jet takes off after 250.0 m, what was its final takeoff velocity?72.2 m/s36.4 m/s250.0 m/s 498.8 m/s3.62 m/s
Question
A fighter jet accelerates at an average rate of 10.43 m/s2 and takes 6.90 sec to take off. If the jet takes off after 250.0 m, what was its final takeoff velocity?72.2 m/s36.4 m/s250.0 m/s 498.8 m/s3.62 m/s
Solution
To solve this problem, we can use the formula for acceleration, which is:
final velocity = initial velocity + (acceleration * time)
Given that the jet starts from rest, the initial velocity is 0. So the formula simplifies to:
final velocity = acceleration * time
Substituting the given values:
final velocity = 10.43 m/s^2 * 6.90 s
final velocity = 71.97 m/s
So, the closest answer to this is 72.2 m/s.
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