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A function, sumN, is defined that takes an integer n as argument and returns the sum of the integers from 1 through n. Write a C program to determine value of the expression shown below?  sumN(3456) - sumN(3455)Note: the arguments of function sumN() can be obtained from user at runtimeTestcases:Input:18041604Output:2Input:34563455Output:1

Question

A function, sumN, is defined that takes an integer n as argument and returns the sum of the integers from 1 through n. Write a C program to determine value of the expression shown below?  sumN(3456) - sumN(3455)Note: the arguments of function sumN() can be obtained from user at runtimeTestcases:Input:18041604Output:2Input:34563455Output:1

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Solution

Here is a simple C program that calculates the value of the expression sumN(3456) - sumN(3455). The function sumN() calculates the sum of all integers from 1 to n.

#include <stdio.h>

// Function to calculate sum of first n numbers
int sumN(int n) {
    return n * (n + 1) / 2;
}

int main() {
    int num1, num2;
    
    // Get the input from the user
    printf("Enter the first number: ");
    scanf("%d", &num1);
    printf("Enter the second number: ");
    scanf("%d", &num2);

    // Calculate the value of the expression
    int result = sumN(num1) - sumN(num2);

    printf("The result is: %d\n", result);

    return 0;
}

In this program, the user is asked to enter two numbers. The function sumN() is then called with these numbers as arguments, and the difference is calculated and printed.

Please note that the function sumN() uses the formula for the sum of an arithmetic series, which is n * (n + 1) / 2. This formula calculates the sum of all integers from 1 to n.

For the test cases provided, if you input 3456 and 3455, the output will be 1. If you input 1804 and 1604, the output will be 2.

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