1234567891011121314#include <stdio.h> int sum(int s, int e) { if (s > e) return 0; else return s + sum(s + 1, e);} int main() { printf("%d", sum(2, 5)); return 0;}
Question
1234567891011121314#include <stdio.h> int sum(int s, int e) { if (s > e) return 0; else return s + sum(s + 1, e);} int main() { printf("%d", sum(2, 5)); return 0;}
Solution
The given text is a C program that calculates the sum of numbers in a given range. Here's a step-by-step explanation of the code:
-
The
#include <stdio.h>is a preprocessor command that includes the standard input/output library in the program. This library allows the program to perform input and output operations. -
The
sumfunction is a recursive function that calculates the sum of numbers fromstoe. Ifsis greater thane, it returns 0, ending the recursion. Otherwise, it addssto the result ofsum(s + 1, e), effectively adding all numbers fromstoe. -
The
mainfunction is the entry point of the program. It calls thesumfunction with arguments 2 and 5, meaning it calculates the sum of numbers from 2 to 5. The result is then printed to the console using theprintffunction. -
The
return 0;statement signifies that the program has ended successfully. It's a good practice to return a value from themainfunction to indicate whether the program has run successfully or not. In this case, 0 usually indicates success.
Similar Questions
2136, 2217, 2541, 3270, 4566, …
123456789101112131415161718#include <stdio.h>int f(int x) { if (x == 2) { return 2; } else { printf("*"); return f(x - 1); }}int main() { int n, i; n = f(6); printf("%d", n); return 0;}
1234567891011121314151617#include <stdio.h> int main() { int x = 20; switch (x) { case 10: if (x == 10) printf("Ten "); case 20: if (x == 20) printf("Twenty "); case 30: printf("Thirty "); default: printf("Other "); } return 0; }
74156 – ? – 321 – 20 + 520 = 69894 Options : 3451 4441 5401 4531
9143 : 9963 :: 6731 : ?Options5666136889649694
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