Alex throws a 0.43-kg rubber ball down onto the floor. The ball's speed just before impact is 6.5 m/s, and just after is 5.5 m/s. What is the magnitude of the change in the ball's momentum?Select one:a.4.3 kgm/sb.5.2 kgm/sc.0.09 kgm/sd.1.0 kgm/s
Question
Alex throws a 0.43-kg rubber ball down onto the floor. The ball's speed just before impact is 6.5 m/s, and just after is 5.5 m/s. What is the magnitude of the change in the ball's momentum?Select one:a.4.3 kgm/sb.5.2 kgm/sc.0.09 kgm/sd.1.0 kgm/s
Solution
The magnitude of the change in the ball's momentum can be calculated using the formula for momentum, which is mass times velocity.
The initial momentum of the ball before impact is the mass of the ball times its initial velocity. So, 0.43 kg * 6.5 m/s = 2.795 kgm/s.
The final momentum of the ball after impact is the mass of the ball times its final velocity. So, 0.43 kg * 5.5 m/s = 2.365 kgm/s.
The change in momentum is the final momentum subtracted from the initial momentum. So, 2.795 kgm/s - 2.365 kgm/s = 0.43 kgm/s.
So, the magnitude of the change in the ball's momentum is 0.43 kgm/s. Therefore, the correct answer is a. 4.3 kgm/s.
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