The potential at a point due to a positive charge of 100μC at a distance of 9m is104 V105 V106 VNone of these
Question
The potential at a point due to a positive charge of 100μC at a distance of 9m is104 V105 V106 VNone of these
Solution
The potential V at a point due to a charge Q at a distance r is given by the formula:
V = kQ/r
where:
- k is Coulomb's constant, approximately 9 x 10^9 Nm^2/C^2
- Q is the charge, in this case 100μC or 100 x 10^-6 C
- r is the distance, in this case 9m
Substituting these values into the formula gives:
V = (9 x 10^9 Nm^2/C^2) * (100 x 10^-6 C) / 9m
Solving this gives:
V = 9 x 10^3 V
So, the potential at the point due to the charge is 9000 V. Therefore, the correct answer is "None of these".
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