The potential at a point due to a charge of 4×10-7C located 10cm away is: Use: K=9×109 Nm2/C2.a.4.5×104Vb.3.6×105Vc.3.6×104Vd.4.5×105V
Question
The potential at a point due to a charge of 4×10-7C located 10cm away is: Use: K=9×109 Nm2/C2.a.4.5×104Vb.3.6×105Vc.3.6×104Vd.4.5×105V
Solution
The electric potential (V) at a point due to a point charge (q) is given by the formula:
V = k*q/r
where: k is Coulomb's constant, r is the distance from the charge.
Given: k = 910^9 Nm^2/C^2, q = 410^-7 C, r = 10 cm = 0.1 m (since 1 m = 100 cm).
Substituting these values into the formula, we get:
V = 910^9 Nm^2/C^2 * 410^-7 C / 0.1 m V = 3610^2 V V = 3.610^4 V
So, the electric potential at the point is 3.610^4 V. Therefore, the correct answer is c. 3.610^4 V.
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