Calculate the mass percent of bromine in CBr4 given the following molar masses: C: 12.01 g/mole; Br: 79.90 g/mole.Group of answer choices11.10%36.22%75.94%92.52%96.38%
Question
Calculate the mass percent of bromine in CBr4 given the following molar masses: C: 12.01 g/mole; Br: 79.90 g/mole.Group of answer choices11.10%36.22%75.94%92.52%96.38%
Solution
To calculate the mass percent of an element in a compound, you need to know the molar mass of the compound and the molar mass of the element in question.
Step 1: Calculate the molar mass of CBr4. The molar mass of CBr4 is the sum of the molar mass of Carbon (C) and four times the molar mass of Bromine (Br).
Molar mass of CBr4 = Molar mass of C + 4 * Molar mass of Br = 12.01 g/mole + 4 * 79.90 g/mole = 12.01 g/mole + 319.6 g/mole = 331.61 g/mole
Step 2: Calculate the mass percent of Bromine (Br) in CBr4. The mass percent of Bromine in CBr4 is the molar mass of Bromine times four (since there are four Bromine atoms in CBr4), divided by the molar mass of CBr4, all multiplied by 100% (to convert the ratio to a percentage).
Mass percent of Br in CBr4 = (4 * Molar mass of Br / Molar mass of CBr4) * 100% = (4 * 79.90 g/mole / 331.61 g/mole) * 100% = (319.6 g/mole / 331.61 g/mole) * 100% = 0.9638 * 100% = 96.38%
So, the mass percent of Bromine in CBr4 is 96.38%.
Similar Questions
What is the ratio of mass percentages of C and Cl in C6H12Cl2? (C-12, H-1, and Cl-35.5) A) 6:2 B) 6:1 C) 1:3 D) 1:6 E) 1:1
In carius method of estimation of halogen 0.15g of an organic compound gave 0. 12 g of AgBr. Find out the percentage of bromine in the compound (atomic weight : Ag = 108, Br = 80)
How many molecules of CH4 are present in 1.85 g CH4, given the following molar masses: (C: 12.01 g/mole; H: 1.01 g/mole)?
If bromine atom is available in the form of, say, two isotopesStructure of Atom(49.7%) andStructure of Atom(50.3%), calculate the average atomic mass of bromine atom.
Determine the percentage by mass of carbon in the amino acid arginine, which has the molecular formula C6H14N4O2. M carbon = 12.01 g mol–1M C6H14N4O2 = 174.24 g mol–1Give the answer rounded to two decimal places.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.