In carius method of estimation of halogen 0.15g of an organic compound gave 0. 12 g of AgBr. Find out the percentage of bromine in the compound (atomic weight : Ag = 108, Br = 80)

To find out the percentage of bromine in the compound, we can use the Carius method of estimation.

Step 1: Calculate the number of moles of AgBr formed. The molar mass of AgBr is the sum of the atomic masses of silver (Ag) and bromine (Br), which is 108 + 80 = 188 g/mol. Using the given mass of AgBr (0.12 g), we can calculate the number of moles using the formula: moles = mass / molar mass moles of AgBr = 0.12 g / 188 g/mol

Step 2: Calculate the number of moles of bromine in AgBr. Since AgBr has a 1:1 ratio of Ag to Br, the number of moles of bromine is the same as the number of moles of AgBr.

Step 3: Calculate the molar mass of bromine. The molar mass of bromine is 80 g/mol.

Step 4: Calculate the mass of bromine in the compound. mass of bromine = moles of bromine * molar mass of bromine

Step 5: Calculate the percentage of bromine in the compound. percentage of bromine = (mass of bromine / mass of compound) * 100

Now, let's plug in the values: moles of AgBr = 0.12 g / 188 g/mol moles of bromine = moles of AgBr molar mass of bromine = 80 g/mol mass of bromine = moles of bromine * molar mass of bromine percentage of bromine = (mass of bromine / mass of compound) * 100

By substituting the values and performing the calculations, you can find the percentage of bromine in the compound.