How many molecules of CH4 are present in 1.85 g CH4, given the following molar masses: (C: 12.01 g/mole; H: 1.01 g/mole)?
Question
How many molecules of CH4 are present in 1.85 g CH4, given the following molar masses: (C: 12.01 g/mole; H: 1.01 g/mole)?
Solution
Sure, here are the steps to calculate the number of molecules in 1.85 g of CH4:
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First, calculate the molar mass of CH4. The molar mass of CH4 is the sum of the molar masses of carbon (C) and hydrogen (H). Since CH4 has one carbon atom and four hydrogen atoms, its molar mass is (112.01 g/mole) + (41.01 g/mole) = 16.05 g/mole.
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Next, calculate the number of moles of CH4 in 1.85 g. The number of moles is the mass of the sample divided by the molar mass. So, the number of moles of CH4 is 1.85 g / 16.05 g/mole = 0.115 moles.
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Finally, calculate the number of molecules. The number of molecules is the number of moles times Avogadro's number (6.022 x 10^23 molecules/mole). So, the number of molecules of CH4 is 0.115 moles * 6.022 x 10^23 molecules/mole = 6.925 x 10^22 molecules.
So, there are approximately 6.925 x 10^22 molecules of CH4 in 1.85 g of CH4.
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