Findtheequationoftheaxisofsymmetryfortheparabolay = x2 − 2x.
Question
Findtheequationoftheaxisofsymmetryfortheparabolay = x2 − 2x.
Solution
The axis of symmetry for a parabola given by the equation y = ax^2 + bx + c is given by the formula x = -b/2a.
In the equation y = x^2 - 2x, a = 1 and b = -2.
Substituting these values into the formula gives:
x = -(-2)/2(1) x = 2/2 x = 1
So, the equation of the axis of symmetry for the parabola y = x^2 - 2x is x = 1.
Similar Questions
Findthevertexoftheparabolay = x2 + 3x.
orWatch a videoFindtheequationoftheaxisofsymmetryfortheparabolay = x2.
Findtheequationoftheaxisofsymmetryfortheparabolay = x2 − 354.Simplify any numbers and write them as proper fractions, improper fractions, or integers.
Findthey -interceptoftheparabolay = x2 − 6x + 4.
Findthey -interceptoftheparabolay = x2 − 65.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.