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The following reaction, between carbon dioxide and nitrogen exists as an equilibrium:2𝐶𝑂2+𝑁2⇌2𝐶𝑂+2𝑁𝑂               𝐾𝑐=2.74The concentrations are measured immediately after the reagents are all added into the reaction vessel as:Carbon dioxide: 1.32 MNitrogen: 1.27 MCarobon monoxide: 1.02 MNitric oxide: 1.09 MWhat is the reaction quotient, Qc, at this moment, to 2 decimal places?

Question

The following reaction, between carbon dioxide and nitrogen exists as an equilibrium:2𝐶𝑂2+𝑁2⇌2𝐶𝑂+2𝑁𝑂               𝐾𝑐=2.74The concentrations are measured immediately after the reagents are all added into the reaction vessel as:Carbon dioxide: 1.32 MNitrogen: 1.27 MCarobon monoxide: 1.02 MNitric oxide: 1.09 MWhat is the reaction quotient, Qc, at this moment, to 2 decimal places?

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Solution

The reaction quotient, Qc, is calculated in a similar way to the equilibrium constant, Kc, but it uses the initial concentrations instead of the equilibrium concentrations.

The equation for Qc is:

Qc = [CO]^2 * [NO]^2 / [CO2]^2 * [N2]

Substituting the given concentrations into the equation gives:

Qc = (1.02)^2 * (1.09)^2 / (1.32)^2 * (1.27)

Qc = 1.04 * 1.19 / 1.74 * 1.27

Qc = 1.24 / 2.21

Qc = 0.56

So, the reaction quotient, Qc, at this moment is 0.56 to 2 decimal places.

This problem has been solved

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