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What is Keq for the reaction N2 + 3H2 2NH3 if the equilibrium concentrations are [NH3] = 3 M, [N2] = 1 M, and [H2] = 2 M?A.Keq = 4.5B.Keq = 0.75C.Keq = 1.5D.Keq = 1.125SUBMITarrow_backPREVIOUS

Question

What is Keq for the reaction N2 + 3H2 2NH3 if the equilibrium concentrations are [NH3] = 3 M, [N2] = 1 M, and [H2] = 2 M?A.Keq = 4.5B.Keq = 0.75C.Keq = 1.5D.Keq = 1.125SUBMITarrow_backPREVIOUS

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Solution

The equilibrium constant expression for the reaction N2 + 3H2 -> 2NH3 is given by:

Keq = [NH3]^2 / ([N2] * [H2]^3)

Substituting the given equilibrium concentrations into this expression gives:

Keq = (3 M)^2 / ((1 M) * (2 M)^3) = 9 M^2 / 8 M^4 = 1.125 M^-2

So, the correct answer is D. Keq = 1.125.

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