Write the expression for equilibriumconstant, pk for the reaction :+ 2 22NO (g) O (g) 2NO (g)in terms of :(i) partial pressure and(ii) mole fraction of the gaseous species
Question
Write the expression for equilibriumconstant, pk for the reaction :+ 2 22NO (g) O (g) 2NO (g)in terms of :(i) partial pressure and(ii) mole fraction of the gaseous species
Solution
To write the expression for the equilibrium constant, Kp, for the reaction 2NO2(g) ⇌ 2NO(g) + O2(g) in terms of partial pressure, we need to consider the stoichiometric coefficients of the reactants and products.
The expression for Kp is given by:
Kp = (PNO)^2 * (PO2) / (PNO2)^2
Where PNO, PO2, and PNO2 represent the partial pressures of NO, O2, and NO2, respectively.
To write the expression for the equilibrium constant, Kc, in terms of mole fraction, we need to consider the number of moles of each species.
The expression for Kc is given by:
Kc = ([NO]^2 * [O2]) / [NO2]^2
Where [NO], [O2], and [NO2] represent the mole fractions of NO, O2, and NO2, respectively.
Note that the expressions for Kp and Kc are related by the ideal gas law, which states that the partial pressure of a gas is proportional to its mole fraction.
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