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A particle moves in a circle of radius 10 cm. Its linear speed is given by v = 5t, where t is in seconds and v is in m/s. The tangential acceleration is:

Question

A particle moves in a circle of radius 10 cm. Its linear speed is given by v = 5t, where t is in seconds and v is in m/s. The tangential acceleration is:

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Solution 1

To find the tangential acceleration, we need to differentiate the linear speed equation with respect to time.

Given that the linear speed v = 5t, we can differentiate it to find the tangential acceleration.

Differentiating v = 5t with respect to t, we get dv/dt = 5.

Therefore, the tangential acceleration is constant and equal to 5 m/s^2.

Solution 2

To find the tangential acceleration, we need to differentiate the linear speed equation with respect to time.

Given that the linear speed v = 5t, we can differentiate it to find the tangential acceleration.

Differentiating v = 5t with respect to t, we get dv/dt = 5.

Therefore, the tangential acceleration is constant and equal to 5 m/s^2.

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